 So the last thing that we want to solve for this problem is the thermal efficiency. And for that we'll use the definition of network divided by qn. And notice this is per unit mass for both of them. What we're going to do, we've already expressed work net in terms of per unit mass through the boiler. We're going to now do the same thing of qn in terms of per unit mass through the boiler. So we'll begin with the boiler itself and try to determine qn. We will be using the first law for that. There's no work in the boiler, kinetic and potential energy are neglected. Now I'm writing the mass flow rate at 4 coming into the boiler. Let's go back and look at our schematic. Let's see where the heck was it. There we go. Okay, mass 4 or 5, they're the same thing because it's basically mass flowing into the boiler and out of the boiler it doesn't matter which we use. I put m.4 there but it could have been m.5 as well. What we'll then do is on a per unit mass basis and we know the enthalpies at both of those states. So that's per kilogram through the boiler. The reheat cycle. So let's take a look at the equation for the reheat. Again, that will be the first law applied to the reheat cycle. And in this case the mass flow rate that we're dealing with is m.6 because that is what is flowing through the reheat. There is no work down in the reheat. So on a per unit mass we divide by m.5. We then use the continuity equation to come up with an expression for m.6 just like we did before. So with that we get the heat into the reheat boiler kilojoules per kilogram through the boiler. So with that we can now evaluate the total heat transfer in as being the boiler plus the reheat kilojoules per kilogram through the boiler. And again that we've evaluated work in in the earlier segments in the same way that is mass flow rate through the boiler we can just divide these two. And when we do that we get the thermal efficiency 44.4 percent. And that is the final answer to part B of the problem. So you can see the thermal efficiency is quite a bit higher than we saw for the simple rank in and that's because we've been increasing the efficiency by doing both the reheat as well as the regeneration. And essentially that's increasing the area under the curve that we talked about increasing the efficiency for rank in it would result in those improvements. And that's what we're seeing here at the higher thermal efficiency. So that concludes the example problem. As you can tell these are kind of laborious calculations but methodical. You write out your process diagram and your process schematic. And then you start getting the state information. You go around determine whatever you can determine. We then went to we evaluated the mass fraction why once we had the mass fraction we could then proceed ahead and determine the mass flow rate knowing the total power out of the power plant. And from there then it was just a matter of evaluating the heat transfer and the thermal efficiency. So that's kind of a summary of the solution set and that concludes this lecture. Thank you.