 Hello and welcome to the session. I am Aashima and I am there to help you with the following problem. Finally, sum of the following AP that is 0.6, 1.7, 2.8, so on to 100 terms. Now before writing the solution let us look at the key idea to the problem. Key idea SN is equal to N by 2 to A plus N minus 1 D where A is the first term, D is the common difference and is the number of terms and SN is the sum of AP. Now let us write the solution given AP is 0.6, 1.7, 2.8, so on to 100 terms. Now here A is equal to 0.6, D is equal to common difference so 1.7 minus 0.6 which is equal to 1.1 and N is equal to 100. Now applying the formula we discuss in key idea that is SN is equal to N by 2 multiplied by 2A plus N minus 1 D which is equal to N is equal to 100 so 100 by 2 multiplied by 2 into 0.6 plus 100 minus 1 into 1.1. Now this gets cancelled by 50 so 15 multiplied by 1.2 plus 99 into 1.1 which is equal to 15 multiplied by 1.2 plus 108.9 which is equal to 50 multiplied by 110.1 which is equal to 5505.0 therefore required sum is 5505. I hope you understood this problem bye and have a nice day.