 Hello and welcome to the session. Let's work out the following problem. It says the resultant of two light parallel forces P and Q acting at A and V, 8 centimeter apart is 40 Newton. If the resultant passes through C where AC is 3 centimeter, find the magnitude of the forces. So let's now move on to the solution. We are given two light parallel forces and their magnitude acting at C and magnitude is 42 Newton and the forces P and Q are 8 centimeter apart. Now we have to find the magnitude of the forces P and Q and since R is the resultant of the forces P and Q. So we have P plus Q is equal to R which is of 40 Newton right and also since this is a system of light parallel forces. So P upon BC is equal to Q upon AC is 3 centimeter and AB is 8 centimeter. Therefore, BC is 5 centimeter. Let's name this as one. So from one we have P into AC is equal to Q into BC. Now AC is 3 centimeter. So P into 3 is equal to Q into 5. So from this we have P is equal to 5 Q by 3. Now we know that P plus Q is 40. So we have P is 5 Q by 3 plus Q is equal to 40. Now taking LCM and simplifying we have 5 Q plus 3 Q upon 3 is equal to 40. Now 8 Q is equal to 120. So this implies Q is equal to 120 by 8. So this implies Q is equal to 15 Newton that is magnitude of the force Q is 15 Newton. Now we have P is equal to 5 by 3 Q 5 by 3 into 15. So this is equal to 25 Newton. So we have magnitude of force P is 25 Newton and magnitude of force Q is 15 Newton. So this completes the question and the session. Bye for now. Take care. Have a good day.