 Hello and welcome to the session. In this session, we will discuss the equation which says that write the following system of equations and the system of equations is given as minus b plus 2c is equal to 4, a plus b minus c is equal to 0, 2a plus 3c is equal to 11 and we have to write this system of equations as a matrix equation. Also we have to identify the coefficient matrix, the variable matrix and the constant matrix. Now let us start with the solution of the given equation. Now here we are given the system of equations and we have to write it in a matrix form. First we have to write different matrix. Now in coefficient matrix the elements, coefficients of the given variables in the system of equations. Now in this matrix first column has coefficients of variable a to a3. Then second column has coefficients of variable b, b1, b2, b3, of variable c, say c1, c2. And here the first row elements that form equation 1 that is this equation, then equation 2 of this equation is equation 3. Now here we have first equation that is minus b plus 2c is equal to 4. Here the variable a is not given as 0. We rewrite 0 into a b plus 2c is equal to 4 then a plus b minus c is equal to 0. Now in the third equation the variable coefficient of b as 0. So it can be written as 0 into b plus 3c is equal to 11. The dimension of coefficient matrix will be, now that these equations are 3, equation 4 and equation 5. The equations that is equation 3, equation 4 and 0, 1 and 2 respectively. In the first column of coefficient matrix 1. Now in second column of coefficient matrix we have that the coefficients are minus 1, 1 and 0. We have coefficients of variable c that is 2 minus 1 and 3 with elements in first row as 0 minus 1, 2 elements in second row as 1, 1 and minus 1, 0. Now let us write the variable that is equal to elements a, b that is matrix with only 1 column. Now let us write also a column matrix the system of equation as 0 minus 1, 2, 0 and 3 matrix only 1 column, 0. Hope you all have enjoyed the session.