 Hello and welcome to the session. In this session we discussed the following question which says solve x plus 2y is equal to minus 1 and 2x minus 3y is equal to 12. Let's proceed with the solution now. We are given the simultaneous linear equations x plus 2y is equal to minus 1 and 2x minus 3y is equal to 12. Let this be equation 1 and this be equation 2. Here the coefficients of the variables in the two equations are different. Now we will solve these two equations for x and y using the substitution method. In the substitution method one equation is solved for one of the variables in terms of the other variable. Like for example when we consider these two equations here we would solve equation 1 for variable x and we would get the value of x in terms of y. Like in this from equation 1 we have x is equal to minus 2y minus 1. Now this value of x would be substituted for x in the second equation. So now substituting the value of x in equation 2 we get 2 into minus 2y minus 1 minus 3y is equal to 12. So this further gives us minus 4y minus 2 minus 3y is equal to 12 that is now we have minus 4y minus 3y is minus 7y is equal to 12 plus 2 that is we transpose this minus 2 to the right hand side. This gives us minus 7y is equal to 14. Now to get the value for y we divide both sides by minus 7 so here minus 7 cancels with minus 7 and 7 2 times is 14 so this means we get the value of y as minus 2. Now that we have got the value for y we can substitute this value of y in this x is equal to minus 2y minus 1. So now substituting y equal to minus 2 in x equal to minus 2y minus 1 we get x is equal to minus 2 multiplied by minus 2 minus 1 that is we have x is equal to 4 minus 1 which is 3 thus we get the value of x as 3. So final answer is x equal to 3 and y equal to minus 2. This completes the session hope you have understood the solution of this question.