 Hi and welcome to the session. My name is Shashi and I am going to help you to solve the following question. Question is solve the following pair of linear equations by substitution method. First equation is root 2x plus root 3y is equal to 0 and the second equation is root 3x minus root 8y is equal to 0. Let us start with the solution now. First of all we will rewrite the two equations given in the question and name them as 1 and 2. Now from equation 1 we equate the value of x and get root 2x is equal to minus root 3y or which implies x is equal to minus root 3 upon root 2y. Now we name this equation as 3 and substitute the value of x from 3 in equation 2. root 3 multiplied by minus root 3 upon root 2y minus root 8y is equal to 0 which implies minus 3 upon root 2y minus 2 root 2y is equal to 0. root 8 is equal to 2 root 2 so we have written it equal to 2 root 2 here. This implies root 2 is the Lcm minus 3y minus 4y is equal to 0 which further implies minus 7y is equal to 0 or we can say y is equal to 0. Now substituting this value of y in equation 3 we get x is equal to minus root 3 upon root 2 multiplied by 0 which implies x is equal to 0 so our required solution is x is equal to 0 and y is equal to 0. Substituting x is equal to 0 and y is equal to 0 you can verify that both the equations 1 and 2 are verified. This completes the session hope you understood the session goodbye.