 Hello and welcome to the session. Let us discuss the following question. It says, find the ratio in which the line joining the point 2-6 and 8-4 is divided by x-axis. Also find the coordinates of the point of division. So let's now move on to the solution. We have to find the ratio in which the line joining the points 2-6 and 8-4 is divided by the x-axis. So let the required ratio k is to coordinate the point of division as x-0 because the point of division lies on x-axis. So that is why the y-coordinate will be 0. Now we should know the section formula which says if a line joining the points x-1, y-1 and x-2, y-2 is divided in the ratio m-1 is to m-2 at the point x-y. Then x is given by m-1, x-2 plus m-1, m-2, x-1 upon m-1 plus m-2 and y is given by m-1, y-2 plus m-2, y-1 upon m-1 plus m-2. So x-1 and it is divided at the point x-0. So x is given by m-1, x-2, m-1 here is k, k plus 1 and y is m-2, y-1 and y-1 is minus 6 plus y-2. Now m-1 is k, y-2 is 4, that is k plus 1. Now where y-coordinate is 0, so we have y is equal to minus 6 plus 4k, so this implies 4k minus 6 is equal to 0 and this implies k is equal to 6 upon 4 and this implies 3 by k is to 1, now k is 3 by 2, so it is 3 by 2 is to 1 and that can be further written as 3 is to 2. The point of division would be x-0, so here we substitute the value of k which is 3 by 2, so it is 3 by 2 into 8 plus 2 upon 3 by 2 plus 1, this is further equal to 24 by 2 plus 2 upon 3 by 2 plus 1. Now this becomes 24 plus 4 upon 2 upon 3 plus 2 upon 2, taking the L7 simplifying, 2 gets cancelled and this becomes the number 28 upon coordinate of point of division is 28 upon 5 and the y-coordinate is 0. So this is 28 upon 5 is 0, so the required ratio is 3 is to 2 and the coordinates of the point of division 28 upon 5 is 0. So this completes the question and the session, bye for now, take care, have a good day.