 Hello and welcome to the session. Let us solve the following problem that says PAB is the midpoint of a line segment between x's, show that the equation of the line is x upon a plus y upon b is equal to 2. Let us now begin with the solution. And first let us interpret the given question in the form of a figure. This one is y axis and let this be the line segment between x's and let RQ be the line segment and P is the midpoint of RQ with coordinates a and b. We have to show that the equation of this line is x upon a plus y upon b is equal to 2. Now let this line makes x intercept u and y intercept as b and this point denotes 0, 0. Now intercept form of equation of line x intercept is u and y intercept is v is given by x upon u plus y upon v is equal to 1. So let us denote this equation by equation number 1. So the point Q has coordinates u, 0 and v is 0 v. Now by midpoint formula we have 0 plus u upon 2 is equal to a and 0 plus v upon 2 is equal to b. So this implies u is equal to 2a and v is equal to 2b. Now substituting the values of u and v in equation number 1 it can further be written as x upon 2a plus y upon 2b is equal to 1 or x upon a plus y upon b is equal to 2. Therefore equation of the line is x upon a plus y upon b is equal to 2 whose midpoint is pab and is between the x's. So this completes the solution. Hope you have understood it. Take care and have a good day.