 Hello and welcome to the session. In this session we discuss the following question which says divide 8A square B minus 6AB plus 14B square by 2AB. Our key idea for this question would be that for dividing a polynomial by monomial divide each term of the polynomial by the monomial. This is the key idea for this question. Now let's move on to the solution. We need to divide 8A square B minus 6AB plus 14AB square by 2AB. So this is the polynomial and we need to divide this polynomial by the monomial 2AB. So I have given in the key idea we need to divide each term of this polynomial by the given monomial. So this would be equal to 8A square B upon 2AB minus 6AB upon 2AB plus 14AB square upon 2AB. Now 2 4 times is 8. Now this A cancels with 1A in the numerator. This B and B gets cancelled. Then 2 3 times is 6. A and A gets cancelled. B and B gets cancelled. Then 2 7 times is 14. This A and A gets cancelled. Now 1B cancels from the numerator with the B in the denominator. So we are left with 4A minus 3 plus 7B. So when we divide this polynomial with the given monomial we get this that is our final answer is 4A plus 7B minus 3. This completes the session. Hope you have understood the solution for this question.