 Hello and welcome to the session. My name is Mansi and I am going to help you with the following question. The question says find the equation of the circle with center minus two three and radius four. So let us start with the solution to this question. First of all we see that equation of the circle with center at the point h k and radius r is given by x minus h the whole square plus y minus k the whole square equal to r square. Now in this case the center that is h k is minus two three. So we have h equal to minus two and k equal to three and r that is radius is equal to four. So we simply put in these values in the formula this and we get x minus h. So x minus of minus two becomes x plus two the whole square plus y minus three the whole square is equal to four square. Now we open the bracket on the left hand side we get x square plus four plus four x plus y square plus nine minus six y equal to sixteen. This implies that x square plus y square plus four x minus six y is equal to sixteen minus nine minus four. This implies that x square plus y square plus four x minus six y now we see that sixteen minus nine minus four is plus three when it comes on the left hand side it becomes minus three equal to zero. So we can say that our answer to the question is that equation of the circle with center minus two three and radius four is given by x square plus y square plus four x minus six y minus three equal to zero. So this is our answer to the question. I hope that you understood the question and enjoyed the session. Have a good day.