 So this one says What is the molarity in the solution made by dissolving 2.355 grams of sulfuric acid into water and diluting to a final volume of 50 milliliters So So the volume of the solution is 15.0 mills, okay, so So It says what is the concentration and molarity of this solution? So the first thing you're going to have to do is figure out Well, what is the number of moles of sulfuric acid that I have? Right, so in order to do that, I have to calculate the molar mass And we're going to put the grams of sulfuric acid down here And you guys don't know sulfuric acid you need to Get your grams all those you're eventually you're going to this is the first one that's good for you to memorize, okay So I'm just going to calculate the molar mass Like was mentioned earlier. It's going to be in liters. So we're going to have to convert that so Again, if you don't know your metric conversions time to learn so 50 divided by 1000 So remember molarity is the derived unit So molarity big M is the derived unit of moles per leader And part of number per volume is concentration So in this case the molarity of your sulfuric acid solution Is going to be 0.0241 moles 0.050 What you say Is your solution concentration is 0.480 molar sulfuric acid Yeah, it's just capital M Okay, so this is the derived unit of moles per leader No, you got a mole molar. Yeah And you got it that's the other thing so now we're going to start learning That we're going to have these derived units that you know, don't show these units here, you know I mean we did we did see one in chapter one. It was called joules, you know But I I don't think I give you any problems. Okay, we're cool