 Hello and welcome to the session. In this session, we discussed the following question which says, in the given figure, t is a point on the side qr of a triangle pqr and s is a point such that rt is equal to st, proof that pq plus pr is greater than qs. Before moving on to the solution, let's recall a fact which says that sum of any two sides of a triangle is greater than the third side. This is the key idea for this question. Now we move on to the solution. We are given in the question that rt is equal to st and we need to prove that pq plus pr is greater than qs. Now in triangle, pqr pr plus pq is greater than qr. So let me know that the sum of the any two sides of a triangle is greater than the third side. So we have taken the sum of the two sides pr and pq and it is greater than the third side which is qr. Now from the figure, you can see that qr is equal to qt plus rt. So this gives us pr plus pq is greater than qt plus rt. Now this further gives us pr plus pq is greater than qt plus st. Since we know that rt is equal to st as it is given to us. So here in place of rt we have written st. Then next we have triangle qst. In this, we consider the sum of the two sides qt and st. So qt plus st and this would be greater than the third side which is qs. Now we have got qt plus st is greater than qs. So now pr plus pq is greater than qt plus st gives us pr plus pq is greater than qs. Or we have pq plus pr is greater than qs. So we have proved this. Hence proved. So this completes the session. Hope you have understood the solution for this question.