 Hello and welcome to the session that has discussed the following question. It says a body moving with velocity of 36 kilometer per hour is not to rest in 10 seconds. Find the retardation and the distance travelled by the body before coming to rest. Let's now move on to the solution. We are given that the initial velocity u is 36 kilometer per hour. Now we'll convert this velocity in meter per second and for that we'll multiply this with 5 by 18. This comes out to be equal to 10 meter per second. Now we are given that the body is brought to rest in 10 seconds. So T is 10 seconds and the final velocity is 0 because body comes to rest. Now we have to find the retardation. Now we know that v is given by u plus at where v is the final velocity, u is the initial velocity, a is the acceleration and T is the time taken. Now let's substitute the values of T, v and u in this formula. So we have 0 is equal to 10 plus 10 a. So this implies a is equal to minus 10 upon 10 that is minus 1. Since a is negative so this is the retardation and this is minus 1 meter per second square. T square is given by u square plus 2 as where v is the final velocity, u is the initial velocity, a is the acceleration, medicines. Here we have retardation. So it will be minus 1 meter per second square and s is the distance traveled. You must write these formula while solving the question. It's very important to write. So let's substitute the values of v, u and a in this formula to obtain the distance traveled is 0 square plus 10 square plus 2 into minus 1 into s. So we have 0 is equal to 100 minus 2s. So this implies 2s is equal to 100 and this implies s is equal to 50. So this implies distance traveled equal to 50 meters and retardation we have obtained as minus 1 meter per second square. So this completes the question. Bye for now. Take care. Have a good day.