 Hello and welcome to this session. In this session we will discuss the question which says that, the schooling football team used four running backs throughout its season. The statistics of each player are given as under. On the first part, we have to organize the data in a matrix, listing players from least attempts to most attempts. In second part, we have to find that what is the dimension of the matrix? In third part, we have to find that what is the value of A23? And in fourth part, we have to add the elements in column 2 and integrate the result. Now let us start with the solution of the given question. Now here, in this table, we have given the players and their statistics. In the first part, we have to form a matrix for the data, listing the players from least attempts to most attempts, i.e. from least number of attempts to the most number of attempts. Now we take properties of statistics in columns. They will be written on dot of matrix and outside the matrix, gains in column 1, attempts in column 2, yards in column 3, and averages in column 4. Now we form a square bracket, representing matrix as inverse from least attempts to most attempts. The player's name will be written outside the brackets inverse, i.e. 94 D, with number of attempts is equal to 142. So we write D in row 2, in row 4. So we have listed the players in rows from least attempts to most attempts, i.e. C has least number of attempts, which is equal to 94 and B has most number of attempts, which is equal to, in row 1, we have player C. So we write entries of player C in respective columns, gains, i.e. 11, that is 94, then we have player D. So we write entries of player D in row 2 inverse. So for player D gains, that is attempts, that is 142, then yard, 38, and lastly, 3.9 entries of player 890 and 5.7. Then in the fourth row, we will write player B in the respective columns. First we will write gains, that is 12, then attempts, that is 161, that is 994, and lastly, average, that is 6.1. So this is our required matrix, we have organized the data, listing the players. From least part, we have to find dimension of this matrix. Now for dimension, we see number of rows and columns of matrix. We can see, we have dimension of this matrix. In the third part, we have to find, now element A and 2, 3 corresponds to second row, I can see, that element is equal to, but we have to add the elements in column 2 and integrate the results. Elements in column 142, 154, that corresponds, second column is 94, then that corresponds to second row and second column, that is the element 42. Similarly, A32 on adding, is equal to, number of attributes given after given question and that's all for this session. Hope you all have enjoyed this session.