 Hi friends, I am Purvind. Today we will work out the fallback question. Find the probability distribution of number of heads and two tosses of a coin. Let us begin with the solution now. Now, let S be the sample space for this experiment. Then we have S is equal to... Now, when two coins are tossed, we get the following two outcomes. That is, head-head, head-tail, tail-tail and tail-head. Now, let X denote the number of heads in two tosses. Now, when there are no heads, then we have X is equal to 0 and probability of X is equal to 1 upon 4. Now, since X denotes the number of heads in two tosses, so when there are no heads, then we have X is equal to 0 and out of these four outcomes, there is only one outcome in which there are no heads when two coins are tossed. So we get probability of X is equal to 1 upon 4. Now, when there is one head, then we have X is equal to 1 and probability of X is equal to 2 upon 4. Because there are two outcomes in which the number of heads is exactly equal to 1 and we have this is equal to 1 upon 2. Now, when there are two heads, then we have X is equal to 2 and probability of X is equal to 1 upon 4. Because there is only one outcome with two heads, out of these four outcomes, thus we have X is equal to 0, 1 or 2. Because maximum number of heads in two tosses of a coin are 2 and we get this as our probability distribution table. So this is our answer. Hope you have understood the solution Bye and take care.