 Hi, and welcome to the session. Let us discuss the following question. The question says, find the coordinates of a point on y-axis which are as a distance of 5 to 2 from the point e having coordinates 3 minus 2 pi. Let's now begin with the solution. We know that coordinates of a point on y-axis are of the form 0, y, 0. So let the coordinates of a point a on the y-axis 0, y, 0. We are given that its distance from point p having coordinates 3 minus 2 pi is 5 root 2 units. So we will find pA by using distance formula. The pA is equal to square root of 3 minus 0 whole square plus minus 2 minus y whole square plus 5 minus 0 whole square. This is equal to square root of y square plus 4y plus 38. Now we are given that distance between p and a is 5 root 2 units. Therefore, 5 root 2 is equal to square root of y square plus 4y plus 38. Squaring both sides, we get y square plus 4y plus 38 is equal to 50. This implies y square plus 4y minus 12 is equal to 0. Now we will factorize this by splitting the middle term. So y square plus 4y minus 12 equal to 0 implies y square plus 6y minus 2y minus 12 is equal to 0. This implies y into y plus 6 minus 2 into y plus 6 is equal to 0. This implies y plus 6 into y minus 2 is equal to 0. And this implies y is equal to minus 6 or y is equal to 2. So coordinates point a 0 minus 6 0 and 0 2 0. This is our required answer. So this completes the session. Bye, and take care.