 Hi, and welcome to the session. Let us discuss the following question. The question says, a particle is moving on a line according to the law. S is equal to tan inverse t plus 80 squared plus bt plus c, where a, b, c are constants. It is given that at t equals to 1, s is equal to 3.5 meters. Velocity is 3.5 meter per second. And acceleration is 1.5 meter per second squared. Find the values of a, b, and c. With this solution, we are given that s is equal to equation number 1. Now velocity and h are given by tt equals to 1 by 1 plus t squared plus 2at plus bt to s by bt2 equals to minus 2t divided by 1 plus t squared whole square plus 2a. Let us name this as equation number 2, and this as equation number 3. Now we will put b equals to 1 and s equals to 3.5 meters in 1. So we get 3.5 equals to tan inverse 1 plus a plus b plus c. This implies a plus b plus c is equal to 3.5 minus pi by 4. This is to 1. This is to 1 by 2 plus. And this implies b is equal to 5 by s to 1.5 in 3 minus 2 pi. Substitute s to 5 pi. So we have 2 into 1 s to 5 by 2 pi by 2 minus 2 is b is equal to 1 by 2.