 Hi and welcome to the session. I am Asha and I am going to help you with the following question that says solve the equation 3x square minus 4x plus 20 upon 3 is equal to 0. A quadratic equation is of the form ax square plus dx plus 3 is equal to 0 where a is not equal to 0 and the solution of this equation will be is equal to minus b plus minus root over v square minus 4ac upon 2a. So, with the help of this idea we are going to solve the given equation. So, this will be our key idea. Let us now begin with the solution and the given equation is 3x square minus 4x plus 20 upon 3 is equal to 0. Now, on comparing it with the standard form of the quadratic equation we find here that a is equal to 3, b is equal to minus 4 and c is equal to 20 upon 3. So, first let us evaluate b square minus 4ac b is minus 4. So, minus 4 is square minus 4 into 3 into 20 upon 3 canceling the common multiples we have 16 minus 80 which is further equal to minus 64 and since minus 1 is equal to iota square. So, this can be written as 64 iota square plus value of root over v square minus 4ac will be equal to root over 64 iota square which will be equal to 8 iota as root over p square minus 4ac is 8 iota. Now, let the given equation be equation number 1. The solution of equation 1 is given by x is equal to minus b plus minus root over v square minus 4ac upon 2a b is minus 4. So, we have minus of minus 4 plus minus root over b square minus 4ac is 8 iota upon 2 into a is 3. So, we have 4 plus minus 8 iota upon 2 into 3. Now, taking 2 common from the numerator we have 2 plus minus 4 iota upon 2 into 3 in canceling the common factors we have 2 plus minus 4 iota upon 3. Let us now separate the real and imaginary parts. So, we have 2 upon 3 plus minus 4 upon 3 iota. So, the solution of the given equation is 2 upon 3 plus minus 4 upon 3 iota. So, this completes the solution. Hope you enjoyed it. Take care and have a good day.