 So let's try this one now Calculate the volume of four moles of argon gas at 8.25 Torr and 27 degrees Celsius So did anything change in that problem? No, so what are we going to use? Just the PV equals nRT. We're not doing PV equals nRT over PV equals nRT Okay, so so remember r is going to be given to you. I'll give it to you right now 0.0821 liter ATM Per mole, but we don't like to write it that way remember when we're writing in it a problem I'll let you try to write it on your own this time, okay? So do we know any of these things PV, n or T? Yeah, we know well definitely n right what is n? 4.00 moles And what else did you say we know? We know PV Right is what? 8.25 Torr You guys know the conversion It's the same thing so the Torr and millimetres of mercury are essentially the same thing It's just Dr. Torr was the guy who came up with the using millimetres of mercury. Okay, so they decided to name it after so But he's dead, so you probably won't mind I'm doing that So I guess just dead. I don't know you might be in a better place Um Okay, so remember we want those in ATM 8.25 divided by 760 So zero point I'm just gonna do zero point zero 18 I'll just keep that Do we know P and we must know T right or we wouldn't be able to do this problem. What is that? 27 plus 273 Which equals 300 Okay, so they're gonna want you to put a decimal place there So make sure you don't do this to one safety. So I think you're going to want to do this to three So what are we going to have to do now? What's the next step? Isolate the variable isolate the V. Okay, so how do we do that? Divide both sides Good job So V equals nRT over P. This is the exact same unlike we did earlier Okay, so Just write it over here again n Rt over T So just plug and check now. We know n 4.00 We know r how we're going to write it very good guys on two lines It's not one of them. Why would you do that? Because it's easier to see the cancelling, you know And then T What's T three all divided by 0.010 So cancel we got numerator denominator moles Kelvin numerator denominator atm Aramiter denominator left with leaders. Is leaders a good volume? Yes Yeah, so we've done it right, you know, so if you get your units, right, you know, you've done it, right, okay I mean, then you got a lot of everything into the calculator, but 0.821 car 0.021 Times 300 all divided by 0.0 Um 0.010 I'm going to say 855 because that's So What do you guys get? 9.0 Yeah, we just did different numbers there, but I got 9.07 Not any of those numbers would be fine. It's just we rounded this number differently Times 10 to the 1 2 3, right? What you guys got? Or 9,076, right So what is the same four moles? at This much pressure and this much temperature is going to be that much fault Okay, is everybody cool with that? Any questions on that one? Questions? Questions? Okay, cool All right