 Okay, let's try, let's try the second mechanism. It says for the following reaction I have a complete mechanism which adequately accounts for the formation of the products, show all the intermediates and curved arrows just like the normal mechanism, okay? But it also gives you the reactant. It has a little circle there, but I like to actually point out the double bonds in the benzene ring and then, what does it say? Does it give us, yeah, a reagent, but it doesn't give us a product, okay? So when we do this, when we're doing the mechanism, we erase that business and write out the reagent so we can use that bond line form and we also put our double bonds and our lone pairs of electrons because remember, double bonds and lone pairs of electrons, those are going to be your nucleophones, okay? So, more bases in this case. The first step, HBr, what is HBr? What type of molecule? Strong acid, a very strong acid. So if you have a strong acid, the first step is always going to be what? Acid base reaction, very good, okay? Just like that. Hey, that's your first step. What do you say SN2 reaction occur here, okay? So what's going to happen here? Remember, you've got a methyl group there, okay? So SN2 reactions, right, they're going to happen on an sp3 hybridized carbon atom, okay? So if we look here, hopefully you can tell that one's sp3 hybridized, right? What about this one? Anybody? Say it louder. I can't really... SP2. SP2, right? Okay. So everybody should be blasting me out of the wall with telling me what the hybridization number is. So since SN2 happens at an sp3 hybridized, they're going to get two organic products from this. Any questions on that? This here, this reaction, SN2. Nucleophile electrified, acid base. That's every step. It's going to be either acid base or nucleophile electrified. Okay? Any questions? Speak now. I ain't taking questions afterwards.