 Good morning friends I am Poojwa and today we will discuss the following question. Find the angle between two vectors vector A and vector B with magnitudes root 3 and 2 respectively having vector A dot vector B is equal to root 6. Let us begin with the solution now. Now the angle between two vectors is given by cos theta is equal to vector A dot vector B upon mod of vector A into mod of vector B. Now here we are given that magnitude of vector A is root 3 so we have mod of vector A is equal to root 3 and magnitude of vector B is 2 so we have mod of vector B is equal to 2. We are also given vector A dot vector B is equal to root 6. Now cos theta is equal to vector A dot vector B which is equal to root 6 so we have root 6 upon mod of vector A which is equal to root 3 into mod of vector B which is equal to 2 and this is equal to now we can write root 6 as root 3 into root 2 upon root 3 into we can write 2 as root 2 square and we get cancelling root 3 and root 3 and root 2 and root 2 we get this is equal to 1 upon root 2 so we get cos theta is equal to 1 upon root 2 this implies theta is equal to cos inverse 1 upon root 2 and this implies theta is equal to 45 degree that is theta is equal to pi by 4. So we have got our answer as pi by 4. Hope you have understood the solution. Bye and take care.