 Hello and welcome to the session. My name is Mansi and I am going to help you with the following question. The question says evaluate the following definite integral that is integral where loma limit of integration is 0 and upper limit of integration is pi sin square x by 2 minus cos square x by 2 dx. So let us start with the solution to this question. We see that integral given to us is sin square x by 2 minus cos square x by 2 dx where limit goes from 0 to pi. Now we see that this is the formula for minus cos x. So this will be equal to integral where limit goes from 0 to pi of minus cos x dx. Now this happens because we see that sin square a minus cos square a is equal to minus cos 2 a. So this is how we get this. Now this is equal to minus integral cos x dx where limit goes from 0 to pi. Now integral of cos x is sin x. So we have minus sin x where limit goes from 0 to pi. This is equal to minus sin pi minus sin 0. This is equal to minus. Now sin pi is 0 and sin 0 is also 0. So we have 0. Our answer to this question is 0. I hope that you understood the question and enjoyed the session. Have a good day.