 Hello and welcome to the session. Let us understand the following question which says, find the points at which the function f given by fx is equal to x minus 2 equal to the part 4 multiplied by x plus 1 to the part 3 has first local maxima, second local minima, third point of inflection. Now let's proceed on to the solution. Given to us is fx is equal to x minus 2 to the power 4 multiplied by x plus 1 to the part 3. Now f dash x is equal to 3 multiplied by x plus 1 the whole square multiplied by x minus 2 equal to the power 4 plus 4 x minus 2 to the part 3 multiplied by x plus 1 to the power 3 by product root. Now for our minima x is equal to 0 multiplied by x minus 2 to the power 4 x plus 1 to the power square multiplied by x minus 2 to the power cube x plus 1 to the power 2 0. Now taking x minus 2 to the power cube and x plus 1 square common, so we are left with 3 multiplied by x minus 2 plus 4 multiplied by x plus 1 is equal to 0. This question, bye and have a nice day.