 Hi and welcome to the session. Today we will discuss the following question. The question says the diagonal of a quadrilateral shaped field is 24 meters and the perpendicular dropped on it from the remaining opposite vertices are 8 meters and 13 meters. Find the area of the field. Here is the given figure of the field. Now before proceeding for the solution, let's recall the formula of area of a quadrilateral. Suppose we have a quadrilateral ABCD in which AC is the diagonal and H1 and H2 are the two perpendicular drawn from the vertices D and B respectively on the diagonal AC. Then the area of the quadrilateral ABCD will be 1 by 2 into D that is the diagonal into H1 plus H2. So here D is the diagonal and H1 and H2 are the two perpendicular drawn from the two vertices on the diagonal. So this is the key idea for this question. See its solution. Now in this question we are given the field which is in the shape of a quadrilateral. Let's name it as PQRS and let us name these points as M and N. So let us write in quadrilateral PQRS PR is the diagonal and diagonal PR is equal to 24 meters. Now in question we are given that the perpendicular is dropped on the diagonal from the remaining opposite vertices are 8 meter and 13 meter. So that means QN is the perpendicular to PR and SM is also a perpendicular to PR. Therefore we can write perpendicular QN is equal to 8 meters, perpendicular SM is equal to 13 meters. Now we want to find the area of the quadrilateral PQRS and we know the formula for the area of quadrilateral that is 1 by 2 into D. D is the diagonal into H1 plus H2. H1 and H2 are the perpendicular from the vertices to the diagonal. So here D is equal to the diagonal PR that is 24 meters. H1 is the perpendicular that is SM to the diagonal. So H1 is equal to 13 meters and H2 is another perpendicular from Q to PR that is 8 meters. Therefore area of PQRS is equal to let us substitute the values of D H1 and H2 in the formula that is 1 by 2 into D that is 24 meters into H1 plus H2. H1 is 13 meters plus H2 is 8 meters. Which is equal to 1 by 2 into 24 into 13 plus 8 meters square that is 1 by 2 into 24 into 21 meters square which on simplifying gives 252 meters square. Therefore area of the field is equal to 252 meters square and thus this is our required answer. With this we finish this session hope you must have understood the question. Goodbye take care and have a nice day.