 Hello and welcome to the session. Let us understand the following problem today. Find the area of a triangle with vertices of the point given in the following. We have 2, 7, 1, 1 and 10, 8. Now before writing the solution, let us look at the key idea. To find the area of a triangle by using determinants, let us see the triangle ABC with vertices x1, y1, x2, y2 and x3, y3. Then area of a triangle ABC is given by equal to half determinant of x1, y1, 1, x2, y2, 1, x3, y3, 1. Now let us write the solution. Here, x1, y1 is equal to 2, 7, x2, y2 is equal to 1, 1 and x3, y3 is equal to 10, 8. Now the required area using the formula given in the key idea, we get half into determinant of 2, 7, 1, 1, 1, 10, 8, 1. Now solving this, we get half into 2 into 1 minus 8 minus 7 into 1 minus 10 plus 1 into 8 minus 10, which is equal to half into 2 into minus 7 minus 7 into minus 9 plus 1 into minus 2. It is equal to half into minus 14 plus 63 minus 2, which is equal to half into minus 14 plus 61, which is equal to half into 47, which is equal to 47 by 2. Hence, the required area is 47 by 2. I hope you understood the problem. Bye and have a nice day.