 Hello and welcome to this session. In this session we discuss the following question which says simplify log 128 upon log 32. Before we move on to the solution, let's discuss one law of logarithm according to which we have log of m to the power of n to the base a is equal to n into log of m to the base a. This is the key idea that we use for this question. Let's proceed with the solution now. We need to simplify log of 128 upon log of 32. As you can see on factorizing 128 we find that 128 is equal to 2 to the power of 7. So we can write this equal to log of 2 to the power 7 upon log of 32 and on factorizing 32 we get 32 equal to 2 to the power of 5. So this would be log of 2 to the power of 5. Now using this key idea that is this law of logarithm we find that this is further equal to 7 log 2 upon 5 log 2. Now this log 2 cancels with log 2 and we are left with 7 upon 5. Therefore we have log 128 upon log 32 is equal to 7 upon 5. This is our final answer. This completes the session. Hope you have understood the solution of this question.