 Hello and welcome to the session. In this session we are going to discuss the following question which says that the population of Wyoming in 2010 was 563,626. The state can be modeled by a rectangle with vertices having coordinates 00, 3490, 0,280 and 349,280 with each unit on coordinate plane as 1 mile, find the population density of Wyoming. And we know that formula to find population density is given by number of people divided by area of the land. With this key idea we shall proceed to the solution. Now we are given that the population of Wyoming is 563,626 in the year 2010 and we need to find the population density of Wyoming. From the key idea we know that population density is given by the formula that is number of people divided by area of the land. For this we need to find the area of the land. So first we model the map of Wyoming using the given coordinates and we are given the coordinates as 00, 3490, 349,280 and 0,280. Here we have plotted them by taking one unit as 1 mile. So here we have got a rectangle whose length is equal to 349 miles and width is given by 280 miles. So area of Wyoming is equal to the area of this rectangle which models map of Wyoming. So required area will be equal to the area of the rectangle which is given by length into width and is equal to length that is 349 miles into width which is equal to 280 miles and this is equal to 97,720 square miles. Now we shall find its population density which is given by number of people divided by area of the land and we know that population of Wyoming that is the number of people in Wyoming is given by 563,626 and area of Wyoming is equal to 97,720 square miles. So population density is equal to 563,626 people upon 97,720 square miles and this is approximately equal to 5.8 people per square mile. So there are about 6 people per square mile in Wyoming which is the required answer. This completes our session. Hope you enjoyed this session.