 Okay, let's take one more question on this Try to get it right now, all of you Here is the question This question comes to the diagram So first draw the diagram What this symbol means 1 kilometer per hour Speed Speed of the river 1 kilometer per hour A swimmer wants to go To point C Starting from A You get From here it wants The swimmer wants to go to C He swims with the speed of 5 kilometer per hour He swims with 5 kilometer per hour With respect to river Okay, so we MR is 5 Should the swimmer swim So basically I have to find theta What is angle theta What is the lack of gravity You know all about that Yes, the swimmer wants to find So 5 cos theta Plus 1 In next direction Find sin theta Success Time taken should be same So time taken Distance divided by velocity By 5 sin theta This should be equal to 400 divided by cos theta Plus 1 Equation to solve Plus 1 Is equal to 5 sin theta So I can have 5 times Cos theta minus sin theta Plus 1 is equal to 0 So cos theta minus sin theta Is equal to minus 1 by 5 What is this How to solve this Then square it If you square it You will get cos square theta Plus sin square theta Then minus of 2 sin theta cos theta Is equal to 1 by 25 So sin of 2 theta Is 1 minus 1 by 25 That is 24 by 25 Not 26 by 25 So 2 theta is Sin inverse of Find out that In motion in 2D In motion in 2D What I will start with the question itself Suppose this is a velocity In all gravity In all gravity The rate is falling at constant velocity The person should Tilt the umbrella So that The person Does not Get the Rain water Okay The person should Hold the umbrella Okay Now if I have to do V minus U This is U So this is Minus U So this is the Direction of Rain velocity With respect to the Observer This is what Of theta Now this is 90 degree So clearly Magnitude of The person's velocity Simple So I Could say that The person is running In an inclined plane Okay I can say For example This one The person is Going Along the Inclined With velocity U Okay And this is the Vertically down Is the velocity Quickly drawn There is an Opposite of U Minus U V minus U Is this 90 degree Theta And then You can V minus You can see that Every time Whenever you have to find The relative velocity You are essentially Subtracting the Observer's velocity Alright And you remember that The actual Power of the plane We have done this problem Right The particle Can move Yes or no Be pointed As if it is going In a straight line So The actual velocity Actual displacement Could be different Actual distance Could be different In terms of Relative Fine So Only time Is something Which is Same Time is not relative Whatever time This point A Has taken to Go from here to here Same time Point A Will take to Go from there to There As in In the relative time This point Is seeing this point As if it is going like this This is the Relative velocity of A This is the Absolute velocity of A Like that We have done this problem Okay Anyways So this was one Small part Which we have left Last Last Okay