 Hi and welcome to the session, I am Deepika here. Let's discuss the question. If the radius of a sphere is measured as 7 meter with an error of 0.02 meter, then find the approximate error in calculating its volume. So let's start the solution. Given radius of the sphere is equal to 7 meter in radius delta R is equal to 0.02 meter. Let V with a volume of a sphere with radius R, therefore V is equal to 4 by 3 pi R cube and dV by dr 4 by 3 into 3 pi R square that is dV by dr is equal to 4 pi R square. Let the approximate error in calculating the volume is delta V. Therefore delta V is equal to dV by dr into delta R and this is equal to 4 pi R square into delta R is given the approximate error is 0.02 and this is equal to 0.08 pi R square. Now by putting R is equal to 7 which is given the radius. Therefore delta V is equal to 0.0 R 8 pi into 7 square and this is equal to 3.92 pi meter cube. Hence the approximate error in calculating its volume is 3.92 pi meter cube and this is our answer. I hope the question is clear to you. Bye and take care.