 Hi Ian, how are you all today? My name is Priyanka and the question says, it cost rupees 2200 to paint the inner curved surface area of a cylindrical vessel 10 meter deep. If the cost of painting is at the rate of rupees 20 per meter square, find first of all the inner curved surface area of the vessel, then the radius of the base and the capacity means we need to find out the volume of the vessel. Now cost of painting the inner surface is given to us as rupees 2200. We know that we can find out the cost of painting the inner surface by multiplying the inner surface area by cost per meter square, then we will get the full cost, right? Also we know that inner surface area is what we need to find out, cost per meter square is given to us as rupees 20 and the total cost is given to us as 2200. So this implies inner surface area that is the inner curved surface area of the vessel is equal to rupees 2200 divided by rupees 20 that is further equal to 110 meter square, right? So this is the answer to the first part, then we need to find out the radius. We know that inner curved surface area's formula is 2 pi r h that means 2 pi r h is equal to 110 meter square that implies 2 into the value of pi is 22 by 7, r is what we need to find out and the height is given to us as 10 meters. So we have it equal to 110 meter square that means the radius is equal to 110 into 7 divided by 2 into 22 10 which is 7 by 4 that implies radius of the vessel is 7 by 4 that is 1.75 meter, right? So this is the answer to the second part and finally the third part is to find out the capacity of the vessel that is pi r square h substituting the value and on simplifying we have the answer to it as 96.25 meter cube also we know that 1 meter cube is equal to 1 kilo liter so we can write the capacity of the vessel as 96.25 kilo liter, right? So this is the required answer to the third part hope you enjoy and understood it well have a nice day.