 Hello all and welcome to the session. Today the question is plot points A32 and B24. These two points are the vertices of a figure which is symmetrical about x is equal to 2 and y is equal to 2. Complete the figure on the graph by writing the geometrical name of the figure. The result of symmetry which is going to be used in the solution is a plane figure is symmetric if and only if there is a reflecting line M such that the figure fits image over M coincide. Now this result will work as a key idea for solving this question and now we will start with the solution. Firstly we have to plot the points A32 and B24 in the graph and you can see here the coordinates of the point A are 3, 2 and the coordinates of the point B are 2, 4 and they are plotted in a graph. xx dash is the x axis and yy dash is the y axis. Now these two points are symmetrical about the line x is equal to 2 and y is equal to 2. Now this is the line x is equal to 2 and this is the line y is equal to 2. Now the reflection of the point A in the line x is equal to 2 is the point C those coordinates are 1, 2 and the reflection of B in the line y is equal to 2 is D those coordinates are 2, 0. Now joining all the points A, B, C and D we are having a figure A, B, C, D which is symmetrical about the lines x is equal to 2 and y is equal to 2. Therefore the completed figure A, B, C, D is symmetrical about the lines x is equal to 2 and y is equal to 2 and this figure A, B, C, D is a rhombus whose vertices are A, 3, 2, D, 2, 4, C, 1, 2 and D, 2, 0. So this is the solution of this question and that's all for this session. Hope you all have enjoyed this session.