 Okay, so we're gonna start with this one here forming this using this dial with HBR excess, so most people put the wrong product on this one And I'd like this is what I was talking about In class how it's easier for me to hit myself in the face that it is for somebody else to hit me in the face No matter how close they are to me. Okay, so that's what we want to think about So let's just so that's excess HBR, right? So let's just erase them So either one of the of course is stronger acid, right? It's gonna look for a base, right? Either one of these is just as good base. Okay, because they're both hydroxyl groups So that's gonna be the first step is that acid base deeper in the nation Directively making the hydronium ion equivalent there, right? Here What is this? This is a good leading group, right? Very stable molecule would be leaving water, right? So we have two options here, right? We have two different nucleophiles one here bromine, which really isn't that great of a nucleophile to begin with, you know And we have this one over here oxygen, which is in fact a better nucleophile and is attached to The molecule where the good leaving group is, right? So it would be my first Guess, you know my first assumption that the oxygen would be the one attacking, you know And so to just validate that, right? You would want to make sure there would be a six or a five or six-membered ring just to you know Be very certain about it. And what would we find if we do one? Two three four five Sac, right? So if we attack that carbon with that oxygen, we'll make a five-membered ring, right? So what'll happen? In fact, let's just notice this leaving group isn't going to leave by itself, right? Because we're going to if we did that it'd make a primary carbocation So this has to be a sn2 reaction and what's going to happen now It's going to deprotonate there you got to form that five-membered cyclic ether, okay? So you got two things working against you, right? Not only is this oxygen attached to the thing And it's a five-membered ring, but it's a better nucleophile that we're only missing, okay? So are there any questions about that?