 Hello and welcome to the session I am Deepika here. Let's discuss a question which says a solid is in the shape of a cone standing on a hemisphere with both their radii being equal to 1 centimeter and the height of the cone is equal to its radius find the volume of the solid in terms of pi. Now we know that the volume of hemisphere is equal to 2 by 3 pi r cube where r is the radius of the hemisphere and volume of cone is equal to 1 by 3 pi r square h where r is the radius of the base of the cone x is the height of the cone. So this is a key idea behind that question. We will take the help of this key idea to solve the above question. So let's start the solution. In this figure let BPC be the hemisphere be the cone on the base of the hemisphere. It is given radius CO of the cone as well as of the hemisphere is equal to 1 centimeter of the cone is equal to radius of the cone and it is equal to 1 centimeter. The volume of the solid formed by joining two basic solids will actually be the sum of the volumes of the constituents. So the volume of the solid is equal to volume of cone as volume of hemisphere according to our key idea volume of cone is equal to 1 by 3 pi r square h and volume of hemisphere is 2 by 3 pi r cube. Let us take 1 by 3 r square common. So volume of solid is equal to 1 by 3 r square into pi h plus 2 pi r. Now r is equal to 1 centimeter and x is also equal to 1 centimeter. So we have volume of solid is equal to 1 by 3 into 1 square into pi into 1 plus 2 pi into 1 centimeter cube because r is equal to 1 centimeter and x is equal to 1 centimeter and this is equal to 1 by 3 into pi plus 2 pi centimeter cube and this is equal to 1 by 3 into 3 pi centimeter cube and volume of solid is equal to pi centimeter cube. Hence the answer for the above question is pi centimeter cube. I hope the solution is clear to you. Bye and take care.