 Hello and welcome to this session. Let us understand the following problem today. Solve the following pair of linear equations. x by a minus y by b is equal to 0 and ax plus by is equal to a square plus b square. Now let us write the solution. Given equations are x by a minus y by b is equal to 0, which can be written as bx minus ay is equal to 0. This is our equation 1 and ax plus by is equal to a square plus b square, which is our equation 2. Now solving equation 1 and 2, first of all, multiplying equation 1 by a and equation 2 by b, we get abx minus a square y is equal to 0, which is our equation 3 and abx plus b square y is equal to b multiplied by a square plus b square. This is our equation 4. Now solving these equations 3 and 4, we see now on subtraction, do not forget to change the sign while subtraction. We see this and this gets cancelled, so we get minus a square minus b square y will give minus of a square plus b square multiplied by y, which is equal to minus b multiplied by a square plus b square. Now we see here that this minus and minus gets cancelled and this a square plus b square gets cancelled, so we are left with y is equal to b. Now substituting y is equal to b in equation 1, we get, we have equation 1 as bx minus ay is equal to 0, which implies bx minus a multiplied by b is equal to 0, which implies bx is equal to ab. Here b and b gets cancelled, which implies x is equal to a, hence x is equal to a and y is equal to b is our required answer. I hope you understood the question, bye and have a nice day.