 Hello, I am welcome to the session. I am Deepika and I am going to help you to solve the following question. The question says, prove that cos A upon 1 minus tan A plus sin A upon 1 minus cot A is equal to sin A plus cos A. So, let's start the solution. So, let's start with left hand side. Now, on the left hand side, we have cos A upon 1 minus tan A plus sin A over 1 minus cot A. Now, this is again equal to cos A over 1 minus tan A can be written as sin A over cos A plus sin A over 1 minus cot A can be written as cos A over sin A. Now, this is again equal to cos A over cos A minus sin A upon cos A plus sin A over sin A minus cos A over sin A and this is again equal to cos A into cos A. Upon cos A minus sin A plus sin A into sin A over sin A minus cos A, now this is equal to cos square A over cos A minus sin A plus sin square A over sin A minus cos A and this can be written as cos square A over cos A minus sin A. Now, let us change sin A minus cos A as cos A minus sin A. Then, we have to change this sign. So, this expression is equal to cos square A over cos A minus sin A minus sin square A over cos A minus sin A. Now, let us take cos A minus sin A as the alzium of these two terms. So, this is equal to cos square A minus sin square A over cos A minus sin A. Now, we know that A square minus B square is equal to A plus B into A minus B. So, by using this formula, we have cos square A minus sin square A is equal to cos A plus sin A into cos A minus sin A upon cos A minus sin A and this is further equal to cos A plus sin A. But, this is our right hand side because on our right hand side of the given identity, we have sin A plus cos A. Hence, our left hand side is equal to right hand side. So, this completes our session. I hope the solution is clear to you. Bye and have a nice day.