 Hi and welcome to the session. My name is Reshi and I am going to help you to solve the following question. Question is, form a pair of linear equations for the following problems and find their solution by substitution method. First part is, the difference between the two numbers is 26 and one number is 3 times the other. Find them. Let us start with the solution now. Reading the question carefully, we can see that there are two numbers unknown. Let us assume that the larger number be equal to x and the other number smaller than x be y. Now according to the question, the difference between the two numbers is 26. So our first equation is x-y is equal to 26. Now the second condition given to us is one number is 3 times the other. In equation 3y, let us name these equations as 1 and 2. Now substituting the value of x from equation 2, in equation 1 we get 3y-y is equal to 26. This implies 2y is equal to 26 which implies y is equal to 26 upon 2 equal to 13. Therefore, y is equal to 13. Now we will substitute the value of y in the equation 2 to get the value of x. Now substituting this value of y in equation 2 we get x is equal to 13 multiplied by 3 which implies x is equal to 39. So the two numbers are 39 and 13 and the required equations are x-y is equal to 26 and x is equal to 3y where x is greater than y. Solutions of the equation are x is equal to 39 and y is equal to 13. This is the required answer. This completes the session. Hope you understood the session. Goodbye.