 Hi and welcome to the session. My name is Chachy and I am going to help you with the following question. Question is, solve the following pair of linear equations by the substitution method. Equations are 3x upon 2 minus 5 over i upon 3 is equal to minus 2 and x upon 3 plus y upon 2 is equal to 13 upon 6. Let us start with the solution now. Multiply in both sides of the given equations in the question by 6 we get 9x minus 10y is equal to minus 12 and other equation would be 2x plus 3y is equal to 13. Let us name these two equations as equation 1 and equation 2. Now from equation 2 we get the value of x equal to 13 minus 3y upon 2. Now let us name this equation as 3. Substituting the value of x from 3 in equation 1 we get 9 multiplied by 13 minus 3y upon 2 minus 10y is equal to minus 12. This implies 117 minus 27y upon 2 minus 10y is equal to minus 12. Multiplying both sides by 2 we get 117 minus 27y minus 20y is equal to minus 24. This implies minus 47y is equal to minus 24 minus 117. This implies y is equal to minus 141 upon minus 47 minus n minus sign get cancelled and 473 that is 141. So we get y is equal to 3. Now substituting this value of y in the equation 3 we get x is equal to 13 minus 3 multiplied by 3 upon 2. This implies x is equal to 13 minus sign upon 2 which implies x is equal to 4 upon 2 or x is equal to 2. So our required solution is x is equal to 2 and y is equal to 3. Substituting x is equal to 2 and y is equal to 3 you can verify that both the equations 1 and 2 are satisfied. Hope you understood the session. Goodbye and take care.