 Hello and welcome to this session. In this session we discussed the following question that says write a unit vector in the direction of vector a equal to 2i cap minus 6k cap plus 3k cap. We know that the unit vector in the direction of vector a is given by a cap which is equal to vector a upon magnitude of vector a. This is the key idea to be used in this question. Let's move on to the solution now. We are given a vector a equal to 2i cap minus 6k cap plus 3k cap. Now magnitude of vector a is equal to square root of 2 square plus minus 6 square plus 3 square. That is we have magnitude of vector a is equal to square root of 4 plus 36 plus 9. That is magnitude of vector a is equal to square root of 49. So we get magnitude of vector a is equal to 7. Now unit vector in the direction of vector a is given by a cap which is equal to vector a upon magnitude of vector a. That is equal to 2i cap minus 6k cap plus 3k cap upon 7. So we have, so the unit vector in the direction of vector a is a cap which is equal to 2 upon 7 i cap minus 6 upon 7 j cap plus 3 upon 7 k cap. So this is the required answer. This completes this session. Hope you have understood the solution of this question.