 Hello and welcome to the session. My name is Mansi and I'm going to help you with the following question. The question says find the center and radius of the circle. 2x squared plus 2y squared minus x equals to 0. So let us start with the solution to this question. Now equation of the circle given to us is 2x squared plus 2y squared minus x equal to 0. Or if we divide throughout by 2 we get x squared plus y squared minus x by 2 equals to 0. Or we can also write it as x squared minus x by 2 plus y squared equals to 0. Now completing the squares within the parenthesis we get x squared minus x by 2 plus 1 by 16 plus y squared minus 1 by 16. Because we see that this is itself a complete square now we need to make this square. So for this we add 1 by 16 and we subtract 1 by 16. So we can write this as x minus 1 by 4 the whole square plus y squared is equal to 1 by 16. Now we know that the equation of the circle with center hk and radius r is minus h the whole square plus y minus k the whole square equals to 1 by equals to r square. Now if we compare this equation to this equation then we have the point hk is 1 by 4 0 because y squared we can write as y minus 0 the whole square. And radius is 1 by 4 because square of 1 by 4 is 1 by 16. So our answer to this question is that center of the circle is 1 by 4 0 and radius is equal to 1 by 4. So this is our answer to the question. I hope that you understood the question and enjoyed the session. Have a good day.