 That function's derivative is automatically occurring which makes your life even simpler and again the same old stuff 1 by T. This can actually be generalized as if you get something like integral f dash x dx by f of x. At this step itself, the numerator is these substitutions so basically it's at x sin x. Now on this side, x square minus x sin x times x of x times 2x minus x cos x. So this will convert it times t to the power 3 by 2 plus c which is 2 times x square minus x sin x to the power of 3 by 2. So my last one will be taken, 4 by 5 is 7. So this will convert it times t to the power 3 by 2 plus c to the power 3 by 2 plus c to the power 3 by 2 plus c to the power 3 by 2 plus c to the power 3 by 2 plus c to the power 3 by 2. So this will convert it times t to the power 3 by 2 plus c to the power 3 by 2 plus c to the power 3 by 2 plus c to the power 3 by 2 plus c to the power 3 by 2 plus c to the power kotex sin a derivative will be minus sin cosec square x dx. So I can get cosec square x dx as minus 2 by sin a t becomes minus 2 t dt by sin a. So minus 2 sin a I can pull out. So your answer is minus 2 by sin a.