 Hello friends, welcome to the session I am at. We are going to discuss matrices. We have to compute the indicated products. Our given matrix is 2, 3, 4, 3, 4, 5, 4, 5, 6 and second matrix is 1 minus 3, 5, 0, 2, 4, 3, 0, 5. So, let A equal to matrix 2, 3, 4, 3, 4, 5, 4, 5, 6 and V equal to matrix 1 minus 3, 5, 0, 2, 4, 3, 0, 5. Now we have to find the product of A and B. Therefore, it can be written as A B equal to 2, 3, 4, 3, 4, 5, 4, 5, 6 multiplied by matrix B which is 1 minus 3, 5, 0, 2, 4, 3, 0, 5. So, this is equal to into 1 plus 3 into 0 plus 4 into 3 then 2 into minus 3 plus 3 into 2 plus 4 into 0, 2 into 5 plus 3 into 4 plus 4 into 5. Similarly for the second row we get 3 into 1 plus 4 into 0 plus 5 into 3 and 3 into minus 3 plus 4 into 2 plus 5 into 0 and 3 into 5 plus 4 into 4 plus 5 into 5 and similarly for the last row 4 into 1 plus 5 into 0 plus 6 into 3 then again 4 into minus 3 plus 5 into 2 plus 6 into 0 then 4 into 5 plus 5 into 4 plus 6 into 5. So, this is equal to 2 plus 0 plus 12 minus 6 plus 6 plus 0, 10 plus 12 plus 20, 3 plus 0 plus 15, minus 9 plus 8 plus 0, 15 plus 16 plus 25, 4 plus 0 plus 18, minus 12 plus 10 plus 0, 20 plus 20 plus 30. So, this is equal to 14, 0, 42, 18 minus 1, 56, 22 minus 2, 70. So, we can say that AB equal to 14, 0, 42, 18 minus 1, 56, 22 minus 2, 70 which is the required matrix. Hope you understood the solution and enjoyed the session. Goodbye and take care.