 Hello and welcome to the session. In this session we discuss the following question which says find the value of k so that the following system of equations has no solution. 3x minus y minus 5 equal to 0, 6x minus 2y minus k equal to 0. The key idea that we use for this question is that a pair of linear equations has no solution when we have that a1 upon a2 is equal to b1 upon b2 is not equal to c1 upon c2. Now let's discuss the solution for this question. Consider the pair of linear equations 3x minus y minus 5 equal to 0, then 6x minus 2y minus k equal to 0. Now from here we have that a1 is equal to 3, b1 is equal to minus 1, c1 is equal to minus 5, then a2 is equal to 6, v2 is equal to minus 2 and c2 is equal to minus k. Now we know that for a pair of linear equations to have no solution a1 upon a2 equal to b1 upon v2 not equal to c1 upon c2. Now let's put the values for a1, a2, b1, v2, c1, c2 that is we get 3 upon 6 equal to minus 1 upon minus 2 not equal to minus 5 upon minus k that is we have 3 upon 6 is equal to 1 upon 2 is not equal to 5 upon k. Now we consider this that is 1 upon 2 not equal to 5 upon k. So from here we get k is not equal to 10. That's the final answer is that for all values of k except 10 the given pair of equations will have no solution. So this completes this session. Hope you have understood the solution for this question.