 So let's start. First of all, from the review, are there any questions that you would like me to go over? Yeah. Five. Love to. So this is what I can do with the tablet, which is why if you want to just watch you can, I can then go like this. Click here, clip. And so number five will appear in the printout that I give you guys. Okay. Yeah. No. Yes. She said five first. The order is not necessarily sequential. It's taken from various exams. And some of it was simply, oh, I got room to fit a short question on this page. Let's stick one there. I was trying to save paper a little bit at least. So number five. I sort of like this question. I sort of like this question. I sort of like this question. What I mean by that is there is a question in my mind that's similar to this. Not quite bang on, but close enough that I think this will help. Okay. So as the projectiles launched over level ground, ground to ground, that's helpful. Speed of that 35 degrees to the horizontal. You know what? I need to draw this. So 240 meters per second at an angle of 35 degrees. Although probably if you had your calculator here, Vitaliy, I might have been willing to do number three, but I can't. That's a nice calculator you got there. Hannah, are you okay finding components? Okay, because that's something we need to be able to do almost in our sleep. Like it's got to be okay. There's VX. There's VY initial. There's VX. And I think VX is going to end up being 240 cosine of 35. And VY is going to end up being 240 sine of 35. And I'll figure out VY, 240 sine 35. I get 137.66. I'll carry a few extra decimals. 137.66. Now, what's this question asking me to find? That's vertical in my mind. Because this is a test situation and I want to save time wherever I can, I'm not even going to bother figuring out horizontal because I don't think I need it. Okay, I wrote that down, but I'm not going to go to my calculator. Just I save myself five seconds and that adds up. So I'm going to think right away here, Hannah, vertical. I've written that right away. I also know this. What's that? Negative 9.8, I hope you said. Right? Oh, and they told me this piece of information, 17 seconds. And they want me to find height. I'll call that a distance Y. So I'm looking for an equation that has V initial, A, T, and D in it. By the way, a good thing to do during this tutorial might be to have your formula sheet in front of you, Hannah, since that's what you'll have for the test anyhow. Taylor. What? Okay. So DY is going to be VY initial T plus a half AY T squared. And now I think it's going to be plug-and-chug. Let's see. We're going to have 137.66 times 17 plus 0.5 times negative 9.8 times 17 squared. No idea what the answer is. Let's see. That times 17 plus 0.5 times negative 9.8 times 17 squared. Looks right. 924. Is that an answer to pick from? Oh, yep, there it is. A, 9.2 times 10 to the second meters. Is that okay? Number three. I think I know number three. I think number three is so easy that it's tough. Oh, no, I stand corrected. Number three. The first part, A, very similar to tally. It's saying how high, maximum height, except ooh. This time doesn't look like they gave us the time. Okay. So let's do three A. I think Taylor, once again, I would dump. I would draw a little picture. 18 meters per second, 26 degrees. And we're going to get Vy initial. Taylor ends up being 18 times the sine of 26. Are you okay with that little shortcut that I took? Because we've seen it fairly often that Vy is sine. Is that okay? Or did it lose you? You're good? Let's crunch the numbers. 18 sine 26, 7.89, one, I guess. What do you want me to find in part A, tally? I'm thinking vertical. So I'll figure out Vx if I need it. But for now, I'm going to go, whoop, undo. Move this down, come on. Down a little bit right to there. And as a little heading, I'm going to write vertical. And right away then, Brandon, I'm going to go Ay is negative 9.8. Do I know time? No. Oh, I know Vy final at the top at the maximum height. How fast are we traveling vertically? Zero. Like that. And I want to find Vy. So I'm looking for an equation that has Vy initial, or V initial, V final, A and D in it. Squared, oh yeah, the squared one. Vf squared equals Vi squared plus 2AD. D is going to be Vf squared minus Vi squared all over 2A, I believe. Zero squared. No, am I right? Minus 7.891 squared, I'll divide it by 2 times negative 9.8. Let's see. By the way, in my maximum height, am I above or below from where I started? Read the question. Think about your maximum height. Are you above or below from where you started? Should I get a positive or a negative answer here? Okay, so this is built in error checks. If I get a negative, I've probably done something silly on my calculator. Equals bracket zero square, I guess zero squared is just zero. Minus 7.891 squared closed bracket. Divided by bracket 2 times negative 9.8, closed bracket. 3.18. Is that what it says in the back? 3.2 maybe? 3.18? You guys know the answers are on the back page, too, right? 3.18 meters. How many marks was that worth, by the way? Sorry, how many? Five. Now, the reason I asked that, Vitaly, is how many marks is part b worth? That would suggest that I should be able to do this in way less work. Part b. So part b asks, how fast will it be traveling when it's at its maximum height? How fast will it be traveling vertically? Zero, you already answered that. In fact, you know what its speed is going to come from? Horizontal. Its speed is going to be, at the top, the horizontal component. Its speed is going to be vx, which I'm pretty sure is going to be cosine, right? It's going to be, where is it, 18 cosine of 26, 16.2 meters per second. And that's because if I think about the projectile like this, right at the top here, the speed is going to be exactly horizontal. No vertical component. And I also could recognize that by looking at the marks and saying, you know, for two marks, I don't think they want me to do that whole Pythagoras, solve, add components, shift 10, shift sign. I think it's just that. It is. It does say 16.2 in the back. Yeah, Adam? Okay. Is that okay? Pardon me? No, no, no, no. That would work? What time? 3.30? Where you working? Well, let's see. See, you're 0 for 3 in getting to these detentions. And I finally got you here. And every time you promised me that you would make up one that you couldn't go to because you couldn't make it in the first place, you haven't showed up. Pardon me? After I hand wrote it on your hand, because I had you today, but you also did that Tuesday of last week when you told me you were going to show up and suddenly I got an email so you couldn't make it. there was a Friday before that when you told me you're gonna show up and then suddenly so if you leave now you still owe me as far as I'm concerned 45 minutes somewhere along the way when for sure think very very carefully long and hard of course this whole conversation is going to be going on the internet with my peers as well with posterity kind of classic gold 45 tomorrow Wednesday you were waiting for him oh man could you do oh anyways have a good day next yeah 13 13 oh and they gave me a lovely picture very nice of them so if I'm understanding this correctly Connor the boat's pointing this way the current's pushing it down this is the resultant if I draw that there's the boat there's the current do I really need to write the o8 if I write vb you'll clue and v boat and then here is my resultant now some of this I know what's the boat traveling in still water that's what I think it's going straight forward at and they gave me this lovely angle here of 32 degrees okay for five marks can I find vc look at my diagram I think I can because it's got a right angle this is going to be good old so katoa my right angle is right there uh corner opposite adjacent to hypotenuse the current what is it I agree what about this 5.6 v boat which trig function this is a little to me this one almost seems a little bit skewed for five marks I think for five marks I'm going to write tangent of 32 equals the mystery current divided by 5.6 keep going Connor how would I get the v current by itself v current is going to be 5.6 tan 32 5.6 tan 32 uh 3.5 I guess 3.499 I'm pretty sure they started with 3.5 probably 3.5 meters per second double check are we correct you have to flip it over and look at the very back 13 a yeah uh b now oh they even added this to the picture for me look at that they put that 185 in here's what I noticed Connor that 185 is in this direction if I'm going to use a velocity it better be in this direction I'm going to use uh this velocity this velocity here so d equals vt what happened to the half at squared we're assuming the river is not speeding up or slowing down we're assuming the boats not speeding up or slowing down and what does b want me to find by the way how many marks is b worth so will I expect it to be less work than a yeah t equals distance divided by v it's going to be 185 divided by 5.6 33 is that all right Connor vitally to be honest that one was so easy that it was almost tough because they gave you so much information that you're almost second guessing yourself saying normally they make me figure some of this out now this one was almost straight grade nine trig what did they ask in part a velocity no what did they ask in part a speed is that a scalar speed is a scalar velocities the vector so you didn't need to ask that question what about direction they didn't want it apparently okay 11 and then which one seven by the way um I'll say this again if you were studying this weekend hopefully you've clued in I put this file here online in other words I'll pick on Connor because I like you had you checked my online answer key because probably you would have figured it out by looking at this and not to be condescending but you'll figure it out better if you have that aha moment when you figure out what the heck I did than me explaining it it's a better way to learn it's not as quick but it's a much better way to learn so don't forget I put this stuff online start taking advantage of it it's a huge help I got kids from all across the province actually using these ones so in that vein Taylor you asked to number 11 okay quick Taylor what do you want me to find what do you think this number is what do you think this number is what do you know this number is what do we got that has distance v final v initial in a unit the squared one could you mind Taylor I'm going to get the d by itself right now without writing up the original formula just to save time so it's vf squared equals vf squared plus 280 I think it's going to be d equals vf squared minus vi squared all over 2a it's going to be 12.8 squared minus 5.2 squared all divided by 2 times 0.85 I'm going to put the top in brackets because there's two terms divided by and there's two terms in the bottom that's what the bottom brackets to two times 0.8 0.85 close bracket 80.5 oh 80 meters and you know I guess to two sig figs it would be 80 not 80.5 because that's a four so I can say you know what that is the correct answer according to however accurate they decided to go um being honest so I think I took this from this question from like a 1994 exam it would get tossed now how many sig figs how many sig figs how many sig figs how many sig figs but every answer was supposed to be two or three mr. do yeah that one's not through they should have put a decimal after or they should have gone 80.5 I bet you they did originally but then they said ah that three-digit answer stands out too many kids are going to pick that by guessing let's make them all two digits you know I your test is old provincial exam questions that you haven't seen that I haven't given you so I went through to make these reviews Italy I went through every exam from 1994 to about 2006 but every so often I would say you know what this question I'm going to keep myself or I've taken these questions and if they weren't two graphics intensive I've just changed the numbers but sometimes you know like that the previous question with the boat I can't do graphics like that I probably would have just used if it's a pretty question I would have kept it as is still learning how to do the fancy graphics okay no it's going to be based on the provincial exam if you do the review we should find it pretty good yes that's because this review is all old provincial exam questions as is your test okay now we'll blocker you so if you're trying to cram at the last minute you're going to find it hard welcome to grade 12 megan which one seven okay so here's a good example of a I've told you about those using principles of physics essay question type dealies first thing megan the key is read the question really really carefully for example I notice it's talking about horizontal and vertical components I better make sure I mention that in my answer yes some kind of an essay type question except I've given you several different approaches that you can use and the first one I think you'll find reasonably straightforward on your test one usually one sometimes two usually one two on every provincial one at the very very end and one is a part b somewhere to have written how you going so back to my initial explanation megan I better make sure I mentioned that and it's talking about the behavior of these velocity components okay I think I'm going to go like this what can you tell me about the behavior of the horizontal velocity component okay I've heard getting higher and I said heard staying constant which of those is correct horizontally what's your acceleration horizontally okay so this is not to make fun of you but listen we cannot get those wrong if you get that wrong that's going to domino through the whole test and it's going to be ugly how ugly like brandon first thing in the morning ugly oh boy they should have seen the faces over there it was amazing okay so here's what I would say in my answer vx constant since ax is zero now what can you tell me about the vertical component of projectile velocities so we had atoms that goes up to the top stops and then comes back down you know what I think I can summarize that in one word what's the opposite of constant I think I'm going to say v y it's changing it's not equal to negative 9.8 but I will say since ay is equal to negative 9.8 fact vertical acceleration is also constant because it never changes negative 9.8 along the year now let's go back to the original question says here's the projectile this motion can be analyzed in terms of horizontal and vertical velocity components have we mentioned components check explain the behavior of these velocity components have we explained how horizontal behaves check have we explained how vertical behaves check now I might even say vertical gets smaller hits zero gets bigger I don't know I think this is good I think I've answered their question and I have this is four out of four okay probably what they would do is they would give one mark for mentioning that somewhere one mark for mentioning that somewhere that's two out of four one mark for mentioning that somewhere and one mark for mentioning that I think that's how they marked it but I can't remember that okay so this one is one that we we've now seen a few different strategies I've plugged in numbers one time a couple of weeks ago right I did a just a good picture one time a couple of weeks we've done a free body diagram in fact your block out I have you for physics today so we did a free body diagram is one of our answers at the very beginning and just wrote a couple of lines and this one here we sort of answered in English although I would argue that that's not much English that's more just a good explanation okay next yeah 31 whoa jumping towards the end Justin got pretty good in physics 11 so let's assume it's a good question to do 31 cliff absolutely a good question to do now you're gonna all find out a question on your test test on your test I'm going to give you a cliff question like this except unfortunately mine is going to be a bit tougher because in this question they gave you the time of flight see it I'm going to make you figure it out I'm going to tell you the height of the cliff and say find time how will you do that you'll solve it vertically you'll have to end up using the quadratic formula or a quadratic solver I don't care which and here's the other key if you're ending up below from where you started make sure you let the vertical distance be negative because it is a displacement not a distance after all now this question not so bad why they gave us time of flight in fact I'm pretty sure Justin this is very very similar to lesson eight in the notes example I think two cliff and they gave us time of flight find the height find the range so I did one just like this but I'll do it again but I'm going to gently say check your notes especially let's clue in on the last lesson of each unit when I probably fine-tuning and making sure there was a couple of examples that I knew you might see in the future making sure I covered them you guys have clued in that that's always an important lesson in for any teacher the last lesson that probably the covering important stuff Taylor you're gonna make it I don't think so so the first thing I'm going to do is uh I'm gonna find vx and vy I'm gonna go components although being fussy it's vy initial because vy is changing vx is going to be 18 coast 25 vy is going to be 18 sign 25 16.31 7.607 what if I had asked you to find vx and vy could you leave your answers like that no go to two or three sig figs and include units and in fact on one of your questions tomorrow or Thursday I do say for two marks I think one mark each find vx find vy the blank the film the blanks make sure then you go to a few sig figs make sure you then you put the units but here this is rub my work I'll carry a few extra decimals the tally question okay what do they want me to find a part a Justin vertical so for part a I would go okay vertical a equals negative 9.8 vy initial equals I just scrolled down 7.67 607 is that what it was yes uh oh they told me time of flight very nice of them 4.2 seconds and I'd like to find d yeah that's why I have a little a right there oh well you can't read that that's my fault let's try that again oh no try that again no better hey um oh this in fact the d's gonna be by itself already it's great let's straight plug and d equals vi t plus one half a t squared it's gonna be 7.607 times 4.2 plus one half times negative 9.8 times 4.2 squared by the way before I even start the numbers am I ending up above or below from where I started from below should I expect a negative or positive displacement here probably expecting a negative let's find out from some numbers times 4.2 plus point five times negative 9.8 times 4.2 squared so I get negative 54.5 meters so the height which is technically a scalar is 54.5 meters but if you left the negative on there I wouldn't freak out it's just we don't talk about cliffs having a negative height so okay that's it b Justin what does b want me to find which distance horizontal dx and that's going to be vxt oh Megan why don't I need to write plus a half a t squared what is my horizontal acceleration zero so that whole thing vanishes good good uh vx is going to be did I calculate vx I did uh 16.31 times time well they told me the time uh 68.5 meters there's my range is that okay number nine I heard somebody go oh yeah so apparently you asked a good question okay okay sorry I now I'll make this a pdf and email it out too or put it online but I won't print it right now because we're still going number nine by the way how many marks is part a now how many marks is part b I'm expecting probably three or four lines for each of these then right if it's a five and two it's probably lots of work and probably plug and chug five marks and two marks split like this probably working working both yep um I need to draw a little picture yeah 35 meters per second angle of 24 degrees some of us there's uh knowing there's there's uh there where am I going there's the x melody and there is vy initial is that okay and uh I'm pretty sure if I recall vy is going to be 35 sine 24 and vx is going to be 35 cos 24 35 sine 24 14.24 31.97 and now I'm going to tackle part a what does part a want me to find it's not a flight okay that means they have to they have to have told me a displacement of some type and they have I don't know how far I traveled horizontally but how high was I when I started ground how high was I when I finished ground you know my vertical displacement is zero so here's I'm going to salvage vertically I'm going to go vertical a equals negative 9.8 vy initial equals 14.24 t equals question mark and then I have two more values now I got dy vertical displacement which you said was zero and I think I also know this one here because I'm starting on the ground and ending on the ground what was my starting vertical velocity 14.24 you know my finishing vertical velocity is negative 14.24 only works if we're starting and ending same height which usually means ground to ground so I got stuck there which equation would be the most convenient I could use the vf squared vi squared 2ad that's got squares in it I don't have time in it they want to know time of flight looking for an equation that has t I think the easiest is going to be double check do I know v final check do I know v initial check do I know a truck then I can find t go you cold okay so you're not just trying to make it hot okay I got the windows open sorry uh what do you want me to find let's get t by itself t is going to be v final minus v initial all over a it's going to be negative 14.24 minus 14.24 divided by negative 9.8 whoop mr. decimal mr. duke 2.9 seconds is that right check in the back am I right am I right am I right am I right yes okay b I like b I like b somewhere on your test I'm going to ask you somewhere to find the magnitude of a velocity somewhere where you're going to no components are going to have to combine now now how long was the projectile in the air for no grand total 2.91 when was it at the top then half of 2.91 don't worry don't worry about it I just don't worry about calculating it when was it at the top then half of 2.91 here's what I want you to realize I'm pretty sure after 2.5 seconds it's on its way down that makes sense in other words if I wanted to draw 2.5 not only is it on its way down it's nearly hit the ground I think as a picture it would look something like that this is the velocity I know this because megan vx never changes what was vx uh 31.97 this here is going to be v y final how can I figure that out why vertical or horizontal vertical okay a y is negative 9.8 v y final I don't know oh but they did tell me the time was a 2.5 seconds 2.5 seconds and I do know v y initial v y initial was 14.24 is that right yeah can I find v y final from this information here yeah which one which equation I don't think the vy squared vf square is going to help me because that's got a d in it and I don't have d here that one works because look time and you know what else is nice vf is already by itself isn't it in that equation isn't it oh okay good vf is vi plus 18 it's 14.24 plus negative 9.8 times 2.5 am I expecting a negative or a positive answer I think I'm expecting a negative answer because I'm pretty sure it's on its way down 14.24 plus negative 9.8 times 2.5 I got negative 10.26 okay and that number is going to go right here 10.26 only how would I find the magnitude Pythagoras and then the angle I think I would find is right here I would use tangent and call it below the horizontal I think I think they want a magnet they wanted uh yeah magnitude and direction I can keep going or do you think that's enough it's up to you keep going okay so for Pythagoras I would go like this v equals 31.97 squared plus 10.26 squared equals square root that 33.6 meters per second opposite adjacent which trig function will I use tangent tangent of theta is opposite over adjacent how do I find an angle inverse tan I get 17.8 degrees and the fancy word for this one is below the horizontal okay melody is that okay yeah yeah okay next 17 17 so easy that it's tough I like 17 I like 17 I like 17 17 17 is a nice question I like 17 Justin what does this want me to find the vector that shows what wants me to find the change in velocity everybody under line map and then I've tried to suggest to you that it's important to memorize something so I'll ask Justin my friend what's changing anything too slow what's changing anything final minus initial what's changing anything one more time what's changing anything oh heck I lied to you one more time what's changing anything okay you have to have that memorized here's why what does this want me to find change in what velocity what's changing anything so if they want me to find change in velocity it's going to be final minus initial how do I subtract vectors I don't what do I do get plus negative that's what I do so you ready Justin what direction is the final velocity read the question very carefully so plus what direction is the initial velocity very read very carefully east now look up what's negative the initial velocity so if you add those two vectors how do we add vectors draw them tip to tail if you add those two tip to tail what do you get for a resultant and if you realize change in anything is final minus initial which means this year you're subtracting vectors how do we subtract vectors less than we don't you add the opposite then it's actually a fairly walk in the parkish question like you don't catch that or you haven't memorized that so what's final minus initial change in anything what's changing anything final minus initial you don't have that memorized you're going to be floundering going on next you say 22 you say 11 times 2 44 divided by 2 110 divided by 5 22 by the way look at part b what does it want us to comment on of what okay I'll answer part b first if I was doing part b I would say well I better make sure I talk about components oh I better first of all copy this question if I'm going to do that you need to copy part a first I can get the whole thing there we go so if I were to do part b I would go well better talk about components components of what oh I better talk about vx and I better talk about ax I better talk about vy I better talk about ay oh what can you tell me about ax what can you tell me about Ay what can you tell me about vx constant what you tell me about vy how many marks was this worth worth? Have I written four things? How much you want to bet that's it? Which it is. Now I'll read the question again. Look at my answers. Comment on the horizontal and vertical components done that of velocity and acceleration. Oh, horizontal velocity, constant, acceleration zero, vertical velocity, changing, acceleration, negative 9.8. And for what it's worth? Because it's always negative 9.8. It's because you haven't done much physics yet. I can't ask you very good or interesting using principles of physics right to explain questions. Give me time. Let's do A. Let's do A. What do you want me to find in part A, Megan? DX. So eventually I'm going to have to go horizontal. But first of all, let's find, let's go horizontal. Let's go vertical. AX is zero. AY is negative 9.8. What was the, oh, VX was, try to get a game history there, 85 at 25, 25 degrees above the horizontal. There's VY initial. There's VX. In fact, to think of as it turned out, Megan, VX ended up being 85 cosine of 25. And VY ends up being 85 sine of 25. You okay with that shortcut, Megan? Good. And let's crunch them. 77., I guess, O4. And then sine, 35.92. Good, so far, so good. What do you want us to find in part A? So if they want me to find the range, what they're really asking for is that. I know this. Do I know time over here? Ah, we're going to find time here. Now that means that I need something else because there's no equation that has only three things in it. I either need the final or the vertical displacement. Are we launching on the ground here, Megan? We're turning to the ground? Ooh. What was my VY initial? 35.92. What's my VY final just for impact? Because we're going from ground to ground. So which equation has those four in it? What do they want me to find? Oh, I need to find time of flight in order to do the actual question. So time of flight is going to be V final minus V initial all over negative not, well, all over A. Let's plug in numbers later, Mr. Doe. Equals final, negative 35.92 minus V initial, positive 35.92 divided by A, negative 9.8. See that battalion? I'm looking around for my calculator and then I realized I get 7.33 or 7.3 units. You know what? Since this is not my final answer, I'll carry a few extra digits. 7.331 seconds. Why does that help me? There it is. It's going to be VX times T. What was VX? 77.04 times 7.331. Is that right? 565? That seems high. What number was this? 22? 22. 560? Close enough. Oh, no it's not. Meters. Next. If you're winding down, I can do a few more if you want. I know I'm winding down, but I can push through. And I have one? Nope. When are you writing, Hannah? Thursday? So you got one extra day. Block, Thursday we'll be writing a slightly different test than Block B. Similar. Some of it, there'll probably be about four questions that actually on the multiple choice overlap, but not enough to make it worth my while. Yeah. There'll be plenty of rooms. I generally give you one page per written, and then for the multiple choice, I give you almost the same amount of room as they give you on the actual provincial. Okay, people are packing up. Okay, hang on then. Right quick.