 Okay, let's try this one now. Okay, so we got Fischer's certification here. This takes carboxylic acid to an acid. Okay? This, a stratification is all based on Le Chatelier's principle because it's going to be acid-base reactions, they're equilibrium reactions. Okay? So the only way you can push this is to put one of the reactants in at a lot. Okay? A high concentration. Okay? And that'll push the reaction better. Okay? So you got two reactants, benzylic acid and methanol. This is going to be in a solvent of methanol. That's the solvent. Okay? Where it says excess, that means excess, excess, excess. You know what I'm saying? It's a solvent. So it's really going to push that reaction towards the right. Okay? And that's why we actually have, you know, this forward arrow there. But you need to put a little drop of acid in there. In fact, that acid is just catalytic. Okay? So I'm going to make your answer. Let's go ahead and do it. So the first step of the reaction, like I thought I didn't need to do, but let's do it anyway, is going to be the reaction of the hydronium ion with methanol. Why? Because there's an immense amount of methanol, you know, relative to the one drop of acid that you put in. So it's highly unlikely that it would stay in the hydronium form to protonate this. Okay? So the first thing that's going to happen is that methanol is going to remove the proton from the hydronium ion. Okay? That, of course, is going to give you the active reagent to start the reaction plus water. So let's go ahead and start this reaction. It was funny. I was asked by one of my students the other day, are you usually alone when you're recording videos? Does nobody ever talks? You know what I'm saying? Just like you're not doing right now. Even though I was trying to get to do it. We can eat it all talking. Yeah, exactly. So for me, I'm like, yeah, I'm sitting there just like talking to the wall, teaching the whiteboarders my friend. But I think that, you know, a lot of YouTube people probably do that, you know, now that I think about it, you know, that would be so weird. Until the medium is made, you know. Until the medium is made. Yeah, sure. If somebody's dormant. It would just be weird to me, you know, to like pretend like I would at least need my cats there or something. Talk to him and be like, you get it? It's actually not a bad idea. It's organic music, is it? That's going to be a stupid little video. There forever, for what, your YouTube archaeologist said, okay, so now you've got ethanol by itself, right? It's going to attack the super electrophile. Remember that protonated carbonyl group is the super electrophile, okay? So when it attacks that, this again is an equilibrium, but all of these reactions you'll see are in equilibrium. It goes from sp2 to sp3. Notice this one doesn't make a stereocenter and it's intermediate. Um, no good. Miss positive George. Yeah. Again, acid-base reaction, right? So like that. We'll do it over to here. So it's still in equilibrium. And you've made H3O plus or another methanol molecule, protonated methanol. Either way, this could probably, it's more likely methanol, you know, since it's the silverware. But, um, doesn't matter. Good look. Another acid-base reaction, right? So it's still in equilibrium. This is just a series, like I said, of acid-base reactions. And, uh, well, after this one nucleophilic nucleophile electrophile. Why does it keep going from there? What's wrong with it like it is? Oh, that's not a very good thing. It's, um, that sp3 hybridized with all of those, uh, oxygens around it. It's not going to stay like that. So, um, it's going to make water here, okay? Um, or the, you know, oxy-oxy cation. That's going to come down. It's a good leaving group, right? It's going to kick that out, okay? So this, again, this water, so let's just look at it. The water could come back and attack. So this is actually the, so we've made our protonated product, right? So that's the ester that we want, okay? But we still got water. We just made that. It could come back and attack like that, right? And then go backwards. But there's so little of this, you know? It's like, you know, you've got a sea of methanol and a couple molecules of water in there. So it's very unlikely that this will come back and attack, you know? So what we can effectively say is because of the concentration difference, this is our forward arrow, okay? Does that make sense? Okay? And then I'm going to erase everything on the top here. So we can do that final step, which is just another acid-base reaction, of course. You can use water or methanol, anything. And in fact, let's just use general base. Probably methanol at this point. Um, well, yeah, and then you're going to wash it out, of course. So maybe water or whatever. That's your product. So if you notice, it's like that same mechanism. You're making that electrophile, right? Super electrophile attack, acid-base, acid-base, acid-base until you get to the, you know, Le Chatelier's principal product. Do you know if that makes sense? Is that cool? Any questions on that one?