 For this example, I'm going to pick a couple of numbers off of our number line. So, for example, five and nine. We know that five plus nine is fourteen. So, when I do this arithmetic in a different base, if I don't come out with something that looks like fourteen and decimal, then we're going to be in trouble. So, in binary, five is one, zero, one. And nine is one, zero, zero, one. So, I'll add those two together. One plus one in binary gives me ten. So, I'll write down a zero and carry a one. Now, I have one plus zero plus zero, which is one. Then I have zero plus one, which is also one. And then one plus zero gives me one. So, I get one, one, one, zero. And if I look over next to fourteen, that is what I see. So, if I do the same thing in, say, octal, I'd have five is still five. Nine here is eleven. So, I have five plus one is six in octal. And then one plus zero is one in octal. So, again, I look over, I see I've got sixteen in octal. Hexadecimal isn't quite so interesting because fourteen is still a single digit. So, we're still kind of stuck memorizing that nine plus five is fourteen in hexadecimal. Alternatively, we can convert both of those two decimal numbers, do the arithmetic, then take fourteen and convert that back to E. Either of those will work for a small problem. We'll want to do something a little more interesting for larger problems though.