 Hello and welcome to the session. Here we will discuss the following question. Solve root x square plus 2 root x plus 1 is equal to 0. Now we will start with the solution. Here we have to solve root x square plus 2 root x plus 1 is equal to 0. Now for solving this equation we will put root x is equal to t. Now putting root x is equal to t we get t square plus 2t plus 1 is equal to 0. Now this implies here we will split the middle term so it will be t square plus t plus t plus 1 is equal to 0. Now combining the first two terms and the last two terms this implies t is common and inside t plus 1 plus from these two 1 is common and inside t plus 1 is equal to 0. Further this implies t plus 1 into t plus 1 is equal to 0. This implies t is equal to minus 1 and minus 1. Therefore root x is equal to minus 1 and minus 1. Now on spreading we get t is equal to 1 and 1. Hence this is the solution of the given question and that's all for this session. Hope you all have enjoyed the session.