 Hello friends, welcome to the session. I am Malka and today we are going to find the roots of the following equation Our equation is x minus 1 upon x equal to 3 where x is not equal to 0 now Let's start with that's all our given equation is x minus 1 upon x equal to 3 which can also be written as x square minus 1 equal to 3x or x square minus 3x minus 1 equal to 0 On comparing it with ax square plus bx plus c equal to 0 we get a equal to 1 b equal to minus 3 and c equal to minus 1 Now we can calculate the value of b that is b square minus 4 ac this means d equal to minus 3 square minus 4 into 1 into minus 1 This implies d equal to 9 plus 4 Therefore d equal to 13 now we can calculate the roots root alpha equal to minus b plus square root of d upon 2a and beta equal to minus b minus square root of d upon 2a Now on substituting the value we get alpha equal to minus of minus 3 Plus square root of 13 upon 2 into 1 This gives alpha equal to 3 plus square root of 13 upon 2 Now similarly we will calculate the value of beta Now we see that on substituting the value we get beta equal to minus of minus 3 minus square root of 13 upon 2 into 1 This gives beta equal to 3 minus square root of 13 by 2 hence the roots are 3 plus square root of 13 by 2 and 3 minus square root of 13 by 2 Which is a required solution. Hope you understood it and enjoyed the session. Goodbye and take care