 Hello and welcome to the session. In this session we discussed the following question which says, the base of an isosceles triangle is 12 cm and one of its equal size is 10 cm. Find the area of the triangle. Now, area of an isosceles triangle is equal to half into b into square root of a square minus b square upon 4, where this b is the base that is the measure of the base of the triangle and a is the measure of the equal size of the triangle. This is the key idea to be used in this question. Let's move on to the solution now. In the question we have that the base is 12 cm that is base of an isosceles triangle say b is equal to 12 cm then the equal size of an isosceles triangle say a is of measure 10 cm so the area of the isosceles triangle is equal to half into the measure of the base which is 12 into square root of a square that is 10 square minus b square which is 12 square upon 4 cm square. This is the area of the isosceles triangle. We have substituted the values for a and b in this formula for the area of an isosceles triangle. So on solving this we get this is equal to now 2 6 times is 12 so 6 into square root of 100 minus 144 upon 4 then 4 36 times is 144 so this is equal to 6 into square root of 100 minus 36. So this is equal to 6 into square root of 64 this is equal to 6 into 8 that is square root of 64 is 8 and so this is equal to 48 cm square therefore we have area of the isosceles triangle is equal to 48 cm square. So 48 cm square is our final answer. This completes the session. Hope you have understood the solutions for this question.