 Hi, and welcome to the session. I am Deepika here. Let's discuss a question. Find the intervals in which the following function is strictly increasing or decreasing. x squared plus 2x minus 5. We know that f is strictly increasing an open interval a, b. If f dash x is positive, that is, it is less than 0 for each x belongs to an open interval a, b. And f is strictly decreasing in an open interval a, b. If f dash x is less than 0 for each x belongs to an open interval a, b. So this is a key idea behind our question. So let's start the solution. Given fx is equal to minus 5. Therefore, f dash x is equal to 2x plus 2 and this is equal to 2 into x plus 1. Now, f dash x is equal to 0 implies x is equal to minus 1. Hence, x is equal to minus 1 divides the real line into two disjoint intervals, minus infinity to minus 1 and minus 1 to infinity. Now, for x less than minus 1, our f dash x is equal to 2 into some negative number and this will be negative only. This implies f dash x is less than 0. This implies fx is strictly decreasing for x less than minus 1 and for x greater than minus 1, f dash x is equal to 2 into some positive number and this will be positive. This implies f dash x is positive or f dash x is greater than 0. This implies fx is strictly increasing for x greater than minus 1. Hence, the answer for the above question is, function is strictly decreasing for x less than minus 1 and strictly increasing for x greater than minus 1. So, this is the answer for the above question. I hope the question is great to you. Myam, take care.