 Hi and welcome to the session, let's work out the following question. The question says find 10th term from each, sorry, it's end of the AP 4914 and so on till 254. So let us see the solution to this question. First we have to find which term is 254, here the first term say A is equal to 4, the common difference that is D is equal to 5. Now we see that Tn that is the nth term is equal to A plus n minus 1 into D or we can say 254 is equal to 4 plus n minus 1 into D that is 5 or 254 minus 4 divided by 5 is equal to n minus 1 or 250 divided by 5 is equal to n minus 1 or n minus 1 is equal to 50 or n is equal to 50 plus 1 that is equal to 51. So 10th term from 51st terms is 51 minus 10 that is 41st term therefore T41 is equal to A plus n minus 1 into D that is equal to 4 plus 41 minus 1 into 5 that is equal to 4 plus 40 into 5 that is equal to 4 plus 200 and that is equal to 204. So our answer to this question is 204. I hope that you understood this solution and enjoyed the session. Have a good day.